....................tolong jawab..............
Penjelasan dengan langkah-langkah:
[tex]( {2}^{ - 5} ) {}^{2} \times {8}^{3} \div 16 = {2}^{ - 10} \times ( {2}^{3} ) {}^{3} \div {2}^{4} = {2}^{ - 10} \times {2}^{9} \div {2}^{4} = {2}^{ - 10 + 9 -4 } = {2}^{ - 5} = \frac{1}{ {2}^{5} } = \frac{1}{32} [/tex]
[answer.2.content]
